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Heat Capacity

In a steam po...

Question

In a steam power plant, the steam enters the turbine at 2 MPa and $400^{\circ} C [h = 3251 k J / k g, s = 7.127 k J / k g K]$ . The condenser pressure is 10 kPa. The mean temperature of heat addition will be

$A t T_{s a t} = {45.8}^{\circ}$

$h_{f} = 191.8 k J / k g h_{g} = 2584.6 k J / k g$
$s_{f} = 0.6491 k J / k g K s_{g} = 8.151 k J / k g K$
199.25

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Solution

The correct option is A 199.25

$h_{1} = 3251 k J / k g, s_{1} = 7.127 k J / k g K$

$h_{4} = h_{3} = h_{f} = 191.8 k J / k g [∴ Pump work is neglected]$

$s_{4} = s_{3} = s_{f} = 0.64191 k J / k g K$

$Mena temperrature of heat addition, T_{m} = \frac{h_{1} - h_{4}}{s_{1} - s_{4}} = \frac{3251 - 191.8}{7.127 - 0.6491}$

$= 472.25 K = {199.25}^{\circ} C$

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