In a straight line motion- a particle starts with velocity 5 m-s towards east- A constant acceleration of 2 m-s2 nbsp-acts on it towards west- The displacement of the particle in third second is- nbsp-

Dear Student Displacement #160;of #160;particle #160;in #160;3 #160;ss3 #160;= #160;ut #160;+12at2s3 #160;= #160;5 #215;3 #160;+12( 2)( ...

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Standard IX

Physics

Acceleration

In a straight...

Question

In a straight line motion, a particle starts with velocity 5 m/s towards east. A constant acceleration of 2 m/s² acts on it towards west. The displacement of the particle in third second is

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Solution

Dear Student

$D i s p l a c e m e n t o f p a r t i c l e i n 3 s s_{3} = u t + \frac{1}{2} a t^{2} s_{3} = 5 \times 3 + \frac{1}{2} (- 2) (3)^{2} = 6 m D i s p l a c e m e n t o f p a r t i c l e i n 2 s s_{2} = u t + \frac{1}{2} a t^{2} s_{2} = 5 \times 2 + \frac{1}{2} (- 2) (2)^{2} = 6 m S o d i s p a l c e m e n t o f p a r t i c l e i n 3 r d s e c o n d i s s_{3} - s_{2} = 6 - 6 = 0$

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In a straight line motion, a particle starts with velocity 5 m/s towards east. A constant acceleration of 2 m/s2 acts on it towards west. The displacement of the particle in third second is

Dear Student Displacement of particle in 3 ss3 = ut +12at2s3 = 5×3 +12(-2)(3)2=6 mDisplacement of particle in 2 ss2 = ut +12at2s2 = 5×2 +12(-2)(2)2=6 mSo dispalcement of particle in 3rd second is s3-s2= 6 -6 =0 Regards

In a straight line motion, a particle starts with velocity 5 m/s towards east. A constant acceleration of 2 m/s² acts on it towards west. The displacement of the particle in third second is