In a structure, A atoms have F.C.C. arrangement, B atoms occupy all the tetrahedral sites and C atoms occupy half the octahedral sites. The formula of the compound is

A_{2} B_{2} C_{2}

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A_{2} B_{4} C

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A B_{2} C

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A_{4} B_{2} C

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Solution

The correct option is B $A_{2} B_{4} C$
No. of ‘A’ atoms = x
No. of ‘B’ atoms = 2x
[ $∵$ Tetrahedral holes are double the number of spheres]

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In a structure, A atoms have F.C.C. arrangement, B atoms occupy all the tetrahedral sites and C atoms occupy half the octahedral sites. The formula of the compound is

The correct option is B A2B4CNo. of ‘A’ atoms = x No. of ‘B’ atoms = 2x [∵ Tetrahedral holes are double the number of spheres]

The correct option is B $A_{2} B_{4} C$
No. of ‘A’ atoms = x
No. of ‘B’ atoms = 2x
[ $∵$ Tetrahedral holes are double the number of spheres]