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Byju's Answer
Standard X
Chemistry
Formation of NaCl Lattice
In a structur...
Question
In a structure, oxide ions are cubical closest packed where as 1/8 of tetrahedral voids are occupied by A+2 cation and 1/2 of octahedral voids are occupied by B+3 cations. The formula for this compound is
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Q.
In the structure of a compound, oxide ions are cubic close packed whereas
1
8
t
h
of tetrahedral voids are occupied by
A
2
+
cation and half of octahedral voids are occupied by
B
3
+
cations. The general formula of the compound having structure is:
Q.
In a closed packed structure of mixed oxides, the lattice is composed of mixed oxides ions. One-eighth of tetrahedral voids are occupied by divalent cations
(
A
2
+
)
while one half of octahedral voids are occupied by trivalent cations
(
B
3
+
)
. The formula of mixed oxide is :
Q.
In a compound, oxides ions form fcc lattice, whereas
1
4
t
h
of tetrahedral voids are occupied by cations
A
2
+
and
1
8
t
h
of octahedral voids are occupied by cations
B
3
+
ions. The simplest formula of the compound is
Q.
In a closed packed structure of mixed oxides, the oxide ions are arranged in hcp array. One eight of tetrahedral voids are occupied by divalent cations (A) while one-half of octahedral voids are occupied by trivalent cations (B). What is the formula of the compound?
Q.
In a metallic oxide, oxide ions are arranged in cubic close packing. One sixth of the tetrahedral voids are occupied by cations
P
and one third of octahedral voids are occupied by the cation
Q
. Deduce the formula of the compound.
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