In a study of equilibrium H2(g)+I2(g)2HI(g) 1mol of H2 and 3 mol of I2 give rise at equilibrium to 1.5 mol of HI. Addition of a further 2 mol of H2 gave an additional 1.5 mol of HI. In above problem, what is Kp at the temperature of the experiment.
A
1
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B
2
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C
4
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D
None of these
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Solution
The correct option is C 4 The expression for the equilibrium constant for two equilibria will be Kp=[HI]2[H2][I2]=x2(1−0.5x)(3−0.5x)=1.52(0.25)(2.25)=4 Here, x=1.5.