In a study of number of accidents per day, the observations for $30$ days were obtained as follows:
$6356432542$
$4053615526$
$2122054616$
Construct a suitable frequency distribution table.

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Solution

The required frequency table is shown below:
No. of accidents Tally marks Frequency

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Similar questions

Q. In a study of number of accidents per day, the observations for 30 days were obtained as follows:

6	3	5	6	4	3	2	5	4	2
4	2	1	2	2	0	5	4	6	1
6	0	5	3	6	1	5	5	2	6

Prepare a frequency distribution table.

Q. In a study of number of accidents per day, the observations for 30 days were obtained as follows:

6,	3,	5,	6,	4,	3,	2,	5,	4,	2,	4,	2,	1,	2,	2,
0,	5,	4,	6,	1,	6,	0,	5,	3,	6,	1,	5,	5,	2,	6

Prepare a frequency distribution table.

Q. A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows:

\begin{matrix} 0.03 & 0.08 & 0.08 & 0.09 & 0.04 & 0.17 0.16 & 0.05 & 0.02 & 0.06 & 0.18 & 0.20 0.11 & 0.08 & 0.12 & 0.13 & 0.22 & 0.07 0.08 & 0.01 & 0.10 & 0.06 & 0.09 & 0.18 0.11 & 0.07 & 0.05 & 0.07 & 0.01 & 0.04 \end{matrix}

(i) Make a grouped frequency distribution table for this data with class intervals as

0.00 - 0.04, 0.04 - 0.08

, and so on.
(ii) For how many days, was the concentration of sulphur dioxide more than

0.11

parts per million?

A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows:

0.03 0.08 0.08 0.09 0.04 0.17

0.16 0.05 0.02 0.06 0.18 0.20

0.11 0.08 0.12 0.13 0.22 0.07

0.08 0.01 0.10 0.06 0.09 0.18

0.11 0.07 0.05 0.07 0.01 0.04

(i) Make a grouped frequency distribution table for this data with class intervals as 0.00 - 0.04, 0.04 - 0.08, and so on.

(ii) For how many days, was the concentration of sulphur dioxide more than 0.11 parts per million?

Question 5 (i)
A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days isas follows:
$\begin{matrix} 0.03 & 0.08 & 0.08 & 0.09 & 0.04 & 0.17 0.16 & 0.05 & 0.02 & 0.06 & 0.18 & 0.20 0.11 & 0.08 & 0.12 & 0.13 & 0.22 & 0.07 0.08 & 0.01 & 0.10 & 0.06 & 0.09 & 0.18 0.11 & 0.07 & 0.05 & 0.07 & 0.01 & 0.04 \end{matrix}$
(i) Make a grouped frequency distribution table for this data with class intervals as 0.00 - 0.04, 0.04 - 0.08, and so on.

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In a study of number of accidents per day, the observations for 30 days were obtained as follows:6 3 5 6 4 3 2 5 4 24 0 5 3 6 1 5 5 2 62 1 2 2 0 5 4 6 1 6Construct a suitable frequency distribution table.

The required frequency table is shown below:No. of accidents Tally marks Frequency

In a study of number of accidents per day, the observations for $30$ days were obtained as follows:
$6356432542$
$4053615526$
$2122054616$
Construct a suitable frequency distribution table.

The required frequency table is shown below:
No. of accidents Tally marks Frequency