For II to be maximum, III has to minimum i.e. 0. In this case, II = 150. But, II can’t be 150 as the maximum possible value in only 100.
We have II +2III = 150
Also I + II + III = 100.
So when III=50 and II =50 then all the equations are getting satisfied, hence II=50 is the minimum and maximum value for II
So, maximum value of II = 50