Question

In a survey among B - school students, 68% of those surveyed were in favour of at least one of the three magazines A, B and C, 38% of those surveyed favoured magazine A, 26% favoured magazine B and 36% favoured magazine C. If 11% of those surveyed favoured all three magazines. What percent of those surveyed favoured more than one of the three magazines?

• A. 25%
• B. 33%
• C. 21%
• D. 26%

Answer 1

The correct option is C 21%

$\alpha +\beta +\gamma =68\alpha +2\beta +3\gamma =(38+26+36)=100and\gamma =11\therefore (\alpha +2\beta +3\gamma )-\left[\right(\alpha +\beta +\gamma )+\gamma ]=\beta +\gamma$
= 100 - [68 + 11]
= 21
Hence 21% favoured more than one magazine.

($\alpha \to$ favoured only one magazine, $\beta \to$ favoured only two magazines, $\gamma \to$ favoured all three magazines)