Let E, H and S be the sets of students who study English, Hindi and Sanskrit, respectively.
Also, let U be the universal set.
Now, we have:
n(E) = 26, n(S) = 48, n(ES) = 8 and n(SH) = 8
Also,
n(EH) = 23
n(E) n(EH) = 23
26 n(EH) = 23
n(EH) = 3
Therefore, the number of students studying English and Hindi is 3
n(EHS) = 18
n(E) n{E(HS)'} = 18
26 n{(EH)(ES)}= 18
26 {3 + 8 n(EHS)} = 18
n(EHS) = 3
Also,
n(EHS) = 24
n(U) n(EHS) = 24
n(EHS) = 76
∴ Number of students studying Hindi = n(EHS) n(E) n(S) + n(EH) + n(ES) + n(SH) n(EHS)
= 76 24 48 + 3 + 8 + 8 3
= 18