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Question

In a survey of 60 people, it was found that 25 people read newspaper H, 26 read newspaper T, 26 read newspaper I, 9 read both H and I, II read both H and T, 8 read both T and I, 3 read all three newspapers. Find :
(i) the number of people who read at least one of the newspapers.

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Solution

Let H=H= set of people who read paper HH
I=I= set of people who read newspaper II
T=T= set of people who read newspaper TT
then n(H)=25,n(T)=26,n(I)=26,n(HI)=9n(H)=25,n(T)=26,n(I)=26,n(H∩I)=9
n(HT)=11,n(TI)=8,n(HTI)=3n(H∩T)=11,n(T∩I)=8,n(H∩T∩I)=3
Number of people who read atleast on newspaper
n(HTT)=n(H)+n(T)+n(I)n(H∪T∪T)=n(H)+n(T)+n(I)
n(HT)n(TI)n(IH)+n(HTI)−n(H∩T)−n(T∩I)−n(I∩H)+n(H∩T∩I)
=25+26+269118+3=52

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