In a system of units- the relations between velocity- acceleration and force are given by v 2- v 1-2- T - a 2- a 1- t - F 2- F 1- T where - and t are constants- Then in this new system- where m is mass and L is lengthA- L2-L1-4-3B- M 2- M 1-c2 T 2C- M 2-2 T 2 M 1D- L2-L1-3-3

The correct option is B M_2=M_1/ϵ^2 τ^2 F_2=f_1/ϵτ……(i), a_2=a_1ϵτ……(ii) & v_2=v_1ϵ ^2/τ……(iii) Divide (i) by (ii) M_2=M_1/ϵ^2 τ^2 ...

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Byju's Answer

Standard XII

Physics

Acceleration

In a system o...

Question

In a system of units, the relations between velocity, acceleration and force are given by $v_{2} = \frac{v_{1} ϵ^{2}}{τ}, a_{2} = a_{1} ϵ τ, F_{2} = \frac{F_{1}}{ϵ τ}$ where $ϵ$ and $τ$ are constants. Then in this new system, (where m is mass and L is length)

$M_{2} = \frac{M_{1}}{ϵ^{2} τ^{2}}$

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$M_{2} = ϵ^{2} τ^{2} M_{1}$

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$L_{2} = \frac{L_{1} ϵ^{4}}{τ^{3}}$

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$L_{2} = \frac{L_{1} τ^{3}}{ϵ^{3}}$

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Solution

The correct option is A
$M_{2} = \frac{M_{1}}{ϵ^{2} τ^{2}}$

$F_{2} = \frac{f_{1}}{ϵ τ} \dots \dots (i)$ ,

$a_{2} = a_{1} ϵ τ \dots \dots (i i)$

$& v_{2} = \frac{v_{1} ϵ^{2}}{τ} \dots \dots (i i i)$

Divide (i) by (ii)

$M_{2} = \frac{M_{1}}{ϵ^{2} τ^{2}}$

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In a system of units, the relations between velocity, acceleration and force are given by v2=v1ϵ2τ,a2=a1ϵτ,F2=F1ϵτ where ϵ and τ are constants. Then in this new system, (where m is mass and L is length)

The correct option is A M2=M1ϵ2τ2 F2=f1ϵτ……(i), a2=a1ϵτ……(ii) & v2=v1ϵ2τ……(iii) Divide (i) by (ii) M2=M1ϵ2τ2

In a system of units, the relations between velocity, acceleration and force are given by $v_{2} = \frac{v_{1} ϵ^{2}}{τ}, a_{2} = a_{1} ϵ τ, F_{2} = \frac{F_{1}}{ϵ τ}$ where $ϵ$ and $τ$ are constants. Then in this new system, (where m is mass and L is length)

The correct option is A
$M_{2} = \frac{M_{1}}{ϵ^{2} τ^{2}}$

$F_{2} = \frac{f_{1}}{ϵ τ} \dots \dots (i)$ ,

$a_{2} = a_{1} ϵ τ \dots \dots (i i)$

$& v_{2} = \frac{v_{1} ϵ^{2}}{τ} \dots \dots (i i i)$

Divide (i) by (ii)

$M_{2} = \frac{M_{1}}{ϵ^{2} τ^{2}}$