In a test called ACSAT, the average marks of $15$ test takers are $240$ . if the marks of $5$ test takers are subtracted, the average marks decrease by $40$ . what are the average marks of $5$ test takers?

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Solution

Compute the required value.
The total marks obtained by all test takers are $240 \cdot 15 = 3600$ .
Since the average marks decrease by $40$ if the marks of $5$ test-takers are subtracted.
Therefore, the total marks obtained by $10$ test-taker are $10 \cdot (240 - 40) = 2000$ .
So, the total marked get by five other than $10$ test-taker are $3600 - 2000 = 1600$ .
Therefore, the average marks of the $5$ subtracted test-takers are $\frac{1600}{5} = 320$ .
Hence, the average marks of $5$ test-takers are $320$ .

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In a test called ACSAT, the average marks of 15 test takers are 240. if the marks of 5 test takers are subtracted, the average marks decrease by 40. what are the average marks of 5 test takers?

In a test called ACSAT, the average marks of $15$ test takers are $240$ . if the marks of $5$ test takers are subtracted, the average marks decrease by $40$ . what are the average marks of $5$ test takers?