In a test, the marks obtained by $15$ students are: $34, 37, 44, 39, 45, 46, 35, 42, 48, 40, 39, 33, 43, 47, 44.$
The probability that a student chosen at random passed the test, if the passing marks are $40$ is:

\frac{8}{15}

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\frac{3}{5}

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\frac{7}{15}

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\frac{11}{15}

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Solution

The correct option is B $\frac{3}{5}$
Number of students getting marks equal to or more than $40 = 9 (44, 45, 46, 42, 48, 40, 43, 47, 44)$
P(pass)= $\frac{Number of students who passed}{Total number of students}$
$= \frac{9}{15} = \frac{3}{5}$ .

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In a test, the marks obtained by 15 students are: 34, 37, 44, 39, 45, 46, 35, 42, 48, 40, 39, 33, 43, 47, 44. The probability that a student chosen at random passed the test, if the passing marks are 40 is:

The correct option is B 35Number of students getting marks equal to or more than 40=9(44, 45, 46, 42, 48, 40, 43, 47, 44)P(pass)=Number of students who passedTotal number of students=915=35.

In a test, the marks obtained by $15$ students are: $34, 37, 44, 39, 45, 46, 35, 42, 48, 40, 39, 33, 43, 47, 44.$
The probability that a student chosen at random passed the test, if the passing marks are $40$ is:

The correct option is B $\frac{3}{5}$
Number of students getting marks equal to or more than $40 = 9 (44, 45, 46, 42, 48, 40, 43, 47, 44)$
P(pass)= $\frac{Number of students who passed}{Total number of students}$
$= \frac{9}{15} = \frac{3}{5}$ .