Question

In a test tube, there is $18g$ of glucose $\left(C_6{H}_{12}{O}_6\right)0.08$ mole of glucose is taken out. Glucose left in the test tube is:

• A. $0.10g$
• B. $0.02g$
• C. $0.10mole$
• D. $3.60g$

Answer 1

Answer: (D)

$3.60g$

Moles of glucose=$\frac{18}{180}=0.1$ moles

Moles of glucose left=$0.1-0.08=0.02$ moles

$\therefore$ Mass of glucose left=$0.02\times 180$

=$3.6g$