Question

In a the hall process, aluminum is produced by the electrolysis of molten $A{l}_2{O}_3$ by the following reactions. How many second would it take to produce enough aluminum by the Hall process to make a case of 24 cans of aluminum soft-drink, if each can uses $5.0gofAl,$ a current of 9650 amp is employed, and the current efficiency of the cell is $90\%$ :

• A.
  $203.2$
• B.
  $148.14$
• C.
  $333$
• D.
  $6.17$

Answer 1

The correct option is B

$148.14$
No. of equivalent of aluminum, $\frac{W}{E}=\frac{I\times \eta \times t}{96500}\frac{24\times 5}{27}\times 3=\frac{9650\times 0.9\times t}{96500}t=148.14sec$