Question

In a thermocouple, the neutral temperature is ${270}^{o}C$ and the temperature of inversion is ${525}^{o}C$. The temperature of cold junction would be

• A. ${30}^{o}C$
• B. ${255}^{o}C$
• C. ${15}^{o}C$
• D. ${25}^{o}C$

Answer 1

The correct option is C ${15}^{o}C$

here, neutral temperature Tn=270oCTn=270oC
temperature of inversion T1=525oCT1=525oC
temperature of cold junction Tc=?Tc=?
As Tn−Tc=Ti−TnTn−Tc=Ti−Tn
⇒Tc=2Tn−Ti=2270oC−525oC⇒Tc=2Tn−Ti=2270oC−525oC
Tc=540oC−525oC=15oC