In a thermodynamic process helium gas obeys the law T - P 2 - 5 - constant- The heat given to a gas when temperature of m moles of He is raised from T to 2T is-

The correct option is C Zero T / P^ 2 / 5 = constant 'or' T= constant× P ^ 2 / 5 ∵ PV=RT ∵ PV=R× constant× P ^ 2 / 5 ∴ P / P ^ ...

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Standard X

Physics

Principle of Calorimetry

In a thermody...

Question

In a thermodynamic process helium gas obeys the law $\frac{T}{P^{2 / 5}}$ = constant. The heat given to a gas when temperature of m moles of $H e$ is raised from $T$ to $2 T$ is:

8RT

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Solution

The correct option is C Zero
$\frac{T}{P^{2 / 5}} =$ constant
$^{'} o r^{'} T = c o n s t a n t \times P^{2 / 5}$
$∵ P V = R T$
$∵ P V = R \times c o n s t a n t \times P^{2 / 5}$
$∴ \frac{P}{P^{2 / 5}} \times V =$ constant
$P^{3 / 5} \times V =$ constant
$o r P V^{5 / 3} =$ constant
$o r {P V}^{γ} =$ constant $(∵ γ = \frac{5}{3} f o r H e)$
Thus, process is adiabatic

$∴ Q = 0$ .

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In a thermodynamic process helium gas obeys the law TP2/5 = constant. The heat given to a gas when temperature of m moles of He is raised from T to 2T is:

The correct option is C ZeroTP2/5= constant′or′T=constant×P2/5∵PV=RT∵PV=R×constant×P2/5∴PP2/5×V=constantP3/5×V=constantorPV5/3=constantorPVγ=constant (∵γ=53 forHe)Thus, process is adiabatic ∴Q=0.

In a thermodynamic process helium gas obeys the law $\frac{T}{P^{2 / 5}}$ = constant. The heat given to a gas when temperature of m moles of $H e$ is raised from $T$ to $2 T$ is: