In a thermodynamic process on an ideal monoatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity X of the system. For a mole of monoatomic ideal gas X=32R ln(TTA)+R ln(VVA). Here, R is gas constant, TA and VA are constants. The List - I below gives some quantities involved in a process and List - II gives some possible values of these qunatitites.
List - IList - II(i) Work done by the system in process 1→2→3(P)13RT0ln2(ii)Change in internal energy in process1→2→3(Q)13RT0(iii)Heat absorbed by the system in process1→2→3(R)RT0(iv) Heat absorbed by the system in process1→2(S)43RT0(T)ΔQ=RT0+RT03ln 2
If the process carried out on one mole of monoatomic ideal gas is as shown in the TV - diagram with P0V0=13RT0. The correct match is -