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Question
In a thermodynamic processes, If the amount of work done on the gas by its surrounding is 320 J and the internal energy is increased by 560 J. Calculate the how much heat is transferred between the gas and its surrounding.
In a thermodynamic processes, If the amount of work done on the gas by its surrounding is 320 J and the internal energy is increased by 560 J. Calculate the how much heat is transferred between the gas and its surrounding.
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Solution
The correct option is A 240 J absorbed
From first law of thermodynamic, Q=ΔU+WAs the work done on the system so it will be negative i.e, W=−320J and since internal energy is increased so it would be positive i.e, ΔU=560JThus, dQ=560−320=240J As Q is positive so the system will absorb heat.
From first law of thermodynamic, Q=ΔU+W
As the work done on the system so it will be negative i.e, W=−320J and since internal energy is increased so it would be positive i.e, ΔU=560J
Thus, dQ=560−320=240J
As Q is positive so the system will absorb heat.
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