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Standard XII

Physics

Multiple Glass Slabs

In a thick gl...

Question

In a thick glass slab of thickness $l$ , and refractive index $n_{1}$ , a cubiodal cavity of thickness $^{'} m^{'}$ is carved as shown in the fig and is filled with a liquid of $R . I . n_{2} (n_{1} > n_{2})$ . The ratio $l / m$ , so that shift produced by this slab is zero when an observer $A$ observes an object $B$ with paraxial rays is

\frac{n_{1} - n_{2}}{n_{2} - 1}

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\frac{n_{1} - n_{2}}{n_{2} (n_{1} - 1)}

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\frac{n_{1} - n_{2}}{n_{1} - 1}

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\frac{n_{1} - n_{2}}{n_{1} (n_{2} - 1)}

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Solution

The correct option is A $\frac{n_{1} - n_{2}}{n_{2} (n_{1} - 1)}$
$S h i f t = (l - m) (1 - \frac{1}{n_{1}}) + m (1 - \frac{1}{n_{2}}) = 0$ .

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In a thick glass slab of thickness l, and refractive index n1, a cubiodal cavity of thickness ′m′ is carved as shown in the fig and is filled with a liquid of R.I.n2(n1>n2). The ratio l/m, so that shift produced by this slab is zero when an observer A observes an object B with paraxial rays is

The correct option is A n1−n2n2(n1−1)Shift=(l−m)(1−1n1)+m(1−1n2)=0.

The correct option is A $\frac{n_{1} - n_{2}}{n_{2} (n_{1} - 1)}$
$S h i f t = (l - m) (1 - \frac{1}{n_{1}}) + m (1 - \frac{1}{n_{2}}) = 0$ .