In a thin prism of glass (refractive index 1.5), which of the following relations between the angle of minimum deviations (δm) and angle of first refraction of light (r) through prism will be correct?
A
δm=r
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
δm=1.5r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
δm=2r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
δm=r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Aδm=r For a thin prism, angle of minimum deviation is given by : δm=(μ−1)A ... (i)
Here, μ= refractive index of prism A= angle of prism
For δ=δm,i=e and r1=r2=r ⇒r1+r2=A
or, 2r=A ... (ii)
From (i) & (ii), δm=(μ−1)2r ⇒δm=(1.5−1)2r
or, δm=(0.5×2)r ∴δm=r