Question

In a throw of a die, what is the probability of getting a 4?
(a) $\frac{2}{3}$
(b) $\frac{1}{4}$
(c) $\frac{1}{6}$
(d) $\frac{1}{3}$

Answer 1

(c) $\frac{1}{6}$

Explanation:
In a single throw of a die, all possible outcomes are:
1, 2, 3, 4, 5, 6
Total number of possible outcomes = 6
Let E be the event of getting a 4.
Then, the favourable outcome is 4
Number of favourable outcomes = 1
∴ Probability of getting a 4 = P (E) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{favorable}\mathrm{outcomes}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{possible}\mathrm{outcomes}}=\frac{1}{6}$