Question

In a throw of two dice, the probability of getting a sum of $10$ is

• A. $\frac{1}{12}$
• B. $\frac{1}{36}$
• C. $\frac{1}{6}$
• D. $\frac{1}{4}$

Answer 1

The correct option is A $\frac{1}{12}$

There are a total of $36$ combinations in throw of $2$ dice.

The sum of $10$ could be obtained in the following cases:

$5+5,4+6,6+4$

That is a total of 3 cases. Therefore the required probability here is:

$\frac{3}{36}=\frac{1}{12}$