Question

In a throw with a pair of symmetrical dice, the probability of obtaining a doublet is

• A. $\frac{1}{6}$
• B. $\frac{2}{3}$
• C. $\frac{1}{4}$
• D. $\frac{1}{2}$

Answer 1

Answer: (A)

$\frac{1}{6}$

When pair symmetrical dice thrown, total cases will be $=6\times 6$
Cases for obtaining a doublet: $(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)=6$ cases
Probability for obtaining a doublet$=\frac{6}{6\times 6}=\frac{1}{6}$