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Standard XII

Mathematics

Sequence

In a town 8...

Question

In a town $85 %$ of the people speak Tamil, $40 %$ speak English and $20 %$ speak Hindi. Also, $32 %$ speak English and Tamil, $13 %$ speak Tamil and Hindi and $10 %$ speak English and Hindi, find the percentage of people who can speak all the three languages.

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Solution

Let number of people be $x$
We need to find $n (T \cap E \cap H) = y$
$x = 0.85 x + 0.4 x + 0.2 x - 0.32 x - 0.13 x - 0.1 x + y$
$y = 0.1 x$
Therefore, the percentage of people who can speak all the three languages is $10 %$ .

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In a town 85% of the people speak Tamil, 40% speak English and 20% speak Hindi. Also, 32% speak English and Tamil, 13% speak Tamil and Hindi and 10% speak English and Hindi, find the percentage of people who can speak all the three languages.

Let number of people be xWe need to find n(T∩E∩H)=yx=0.85x+0.4x+0.2x−0.32x−0.13x−0.1x+yy=0.1xTherefore, the percentage of people who can speak all the three languages is 10%.

In a town $85 %$ of the people speak Tamil, $40 %$ speak English and $20 %$ speak Hindi. Also, $32 %$ speak English and Tamil, $13 %$ speak Tamil and Hindi and $10 %$ speak English and Hindi, find the percentage of people who can speak all the three languages.

Let number of people be $x$
We need to find $n (T \cap E \cap H) = y$
$x = 0.85 x + 0.4 x + 0.2 x - 0.32 x - 0.13 x - 0.1 x + y$
$y = 0.1 x$
Therefore, the percentage of people who can speak all the three languages is $10 %$ .