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Transformer

In a transfor...

Question

In a transformer, number of turns in primary and secondary are 500 and 2000 respectively. If current in primary is 48 A, current in the secondary is :

A

144 A

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B

24 A

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C

48 A

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D

12 A

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Solution

The correct option is D 12 A
We know that $\frac{I_{p}}{I_{s}} = \frac{N_{s}}{N_{p}}$
so $\frac{48}{I_{s}} = \frac{2000}{500}$
$I_{s} = 12 A$

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