Question

In a transformer, the number of turns in the primary and secondary coils are 2000 and 4000 respectively. If the primary coil is connected across 120 V AC, the potential difference across each turn of the secondary coil will be :

• A. 0.08 V
• B. 0.05 V
• C. 0.24 V
• D. 0.06 V

Answer 1

Answer: (D)

0.06 V

Given : $N_S=4000$, $N_P=2000$ and $V_P=120$ volts

As we know that,
$\frac{V_S}{V_P}=\frac{N_S}{N_P}$
$V_S=V_P\cdot \frac{N_S}{N_P}=\frac{4000}{2000}\times 120$
Thus we get $V_S=240$ volts
$\therefore$ Potential difference across each turn $=\frac{240}{4000}=0.06V$