Question

In a transformer, the number of turns in the primary coil is 140 and that in the secondary coil is 280. If the current in the primary coil is 4A, then that in the secondary coil is

• A. 4 A
• B. 2 A
• C. 6 A
• D. 10 A

Answer 1

The correct option is B 2 A

In a transformer, the number of turns in the primary coil is 140 and that in the secondary coil is 280. If the current in the primary coil is 4A, then that in the secondary coil is

$\frac{N_1}{N_2}=\frac{I_2}{I_1}$

$I_1=\frac{N_1\ast I_1}{N_2}=\frac{140\ast 4}{280}=2A$