In a transformer there are 10000 turns in primary coil and 25000 turns in secondary coil- An AC source of emf - 50 sin- t V is applied across primary coil- find the peak emf across secondary coil in ideal conditions-

As per given data, turns ratio, N_PN_S=1000025000=12.5 This is a step up transformer. Using transformer equation, we have ℰ_Pℰ_S = N_PN_S ℰ_S = N_SN_P×ℰ_P ...

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Standard X

Physics

Step-Up and Step-Down Transformer

In a transfor...

Question

In a transformer there are $10000$ turns in primary coil and $25000$ turns in secondary coil. An $AC$ source of emf $E = 50 sin π t$ $V$ is applied across primary coil, find the peak emf across secondary coil in ideal conditions.

75 V

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100 V

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125 V

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250 V

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Solution

The correct option is C $125 V$
As per given data,

turns ratio, $\frac{N_{P}}{N_{S}} = \frac{10000}{25000} = \frac{1}{2.5}$

This is a step-up transformer.

Using transformer equation, we have

$\frac{E_{P}}{E_{S}} = \frac{N_{P}}{N_{S}}$

$E_{S} = \frac{N_{S}}{N_{P}} \times E_{P} = \frac{2.5}{1} \times 50 V$

$∴ E_{S} = 125 V$

Hence, option $(C)$ is correct.

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In a transformer there are 10000 turns in primary coil and 25000 turns in secondary coil. An AC source of emf E=50sinπt V is applied across primary coil, find the peak emf across secondary coil in ideal conditions.

The correct option is C 125 VAs per given data, turns ratio, NPNS=1000025000=12.5 This is a step-up transformer. Using transformer equation, we have EPES=NPNS ES=NSNP×EP=2.51×50 V ∴ES=125 V Hence, option (C) is correct.

In a transformer there are $10000$ turns in primary coil and $25000$ turns in secondary coil. An $AC$ source of emf $E = 50 sin π t$ $V$ is applied across primary coil, find the peak emf across secondary coil in ideal conditions.