Question

In a transistor amplifier, $\beta =62,R_L=5000\Omega$ and internal resistance of the transistor is $500\Omega$. The voltage amplification of the amplifier will be

• A. $500$
• B. $620$
• C. $780$
• D. $950$

Answer 1

Answer: (B)

$620$

Current gain, $\beta =62$
$R_L=5000\Omega$
$R_I=500\Omega$
Hence, resistance gain = $\frac{R_L}{R_i}$
Resistance gain = $\frac{5000}{500}=10$

Voltage gain = current gain $\times$ resistance gain
Voltage gain = $62\times 10=620$