Question

In a trapezium $ABCD$, $AB||CD$. If $\angle A={60}^{\circ }$ then $\angle D$ is equal to

• A. ${110}^{\circ }$
• B. ${120}^{\circ }$
• C. ${70}^{\circ }$
• D. ${300}^{\circ }$

Answer 1

The correct option is B ${120}^{\circ }$

It is given that $AB||CD$ and $\angle A={60}^{\circ }$.

As we know that, the sum of angles on the same side of the transversal is equal to ${180}^{\circ }$. So,

$\begin{array}{cc}\angle A+\angle D& ={180}^{\circ }\\ \angle D& ={180}^{\circ }-{60}^{\circ }\\ & ={120}^{\circ }\end{array}$