Question

In a trapezium. ABCD, $\angle ADC={110}^o$. Find $\angle A$.

• A. ${50}^o$
• B. ${60}^o$
• C. ${70}^o$
• D. ${80}^o$

Answer 1

The correct option is C ${70}^o$

In a trapezium, AB || CD
$\therefore$ sum of adjacent angles $={180}^o$
$\angle D+\angle A={180}^o$
$\angle A={180}^o-\angle D={180}^o-{110}^o$
$\angle A={70}^o$