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Question

In a trapezium ABCD, O is the point of intersection of AC and BD, AB CD and AB=2CD. If the area of ΔAOB=84cm2, find the area of ΔCOD.

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Solution

ABCD is a trapezium in which, AB CD and diagonals AC and BD intersect each other at O.
In ΔAOB and ΔCOD we have
1=2 [Alt s]
3=4 [vert opp. \angle s\therefor \Delta AOB \sim \Delta COD$
[By AA criterion of similarity]
ar(ΔAOB)ar(ΔCOD)=(2CD)2(CD)2
[AB = 2CD (Given)]
=4CD2CD2=4
=84ar(ΔCOD)=4;
ar(ΔCOD)=84+4=21cm2
1029249_348181_ans_f8b5aa834f7c419faa3de0ac75048162.jpg

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