Question

In a trapezium $PQRS,PQ\parallel RS$; and $\angle P={70}^{\circ }$ and $\angle Q={80}^{\circ }$. Calculate the measure of $\angle S$ and $\angle R$

Answer 1

In the trapezium $PQRS$, $\angle P$ +$\angle S$ = ${180}^{\circ }$ (Supplementary angles)
$\angle S$ = ${180}^{\circ }-{70}^{\circ }={110}^{\circ }$
$\angle Q$ + $\angle R$ = ${180}^{\circ }$ (Supplementary angles)
$\angle R$ = ${180}^{\circ }-{80}^{\circ }$ = ${100}^{\circ }$