Question

In a trapezium, the measures of parallel sides are 20 cm and 10 cm. Its non-parallel sides are congruent, each measuring 13 cm.
Find the area of the trapezium.

Answer 1

We can see that, $BC=\frac{20-10}{2}=5$ as non-parallel sides are congruent

Now, in $△ABC$

$A{B}^2+B{C}^2=A{C}^2\Rightarrow AB=\sqrt{{13}^2-5^2}=\sqrt{144}=12$

Now, Area of trapezium $=\frac{10+20}{2}\ast 12=180c{m}^2$