Question

In a trapezium whose parallel sides measure 12 cm and 10 cm and the distance between them is 8 cm. Find the area of trapezium---

• A. 84 $c{m}^2$
• B. 48 $c{m}^2$
• C. 88 $c{m}^2$
• D. 188 $c{m}^2$

Answer 1

Answer: (C)

88 $c{m}^2$

Area of trapezium = $\frac{h}{2}(a+b)$
= $\frac{8}{2}(12+10)$
= 4 $\times$ 22 = 88 $c{m}^2$