CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a treasure hunt, Team A collected 6 sacks containing 100 coins each, 5 sacks containing 10 coins each, and 6 more coins. Team B collected 8 sacks containing 100 coins each, 2 sacks containing 10 coins each, and 5 more coins.
Which of the following statements is correct?

A
Team A collected more coins than Team B.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both teams collected the same number of coins.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Team B collected more coins than Team A.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Team B collected more coins than Team A.
Team A collected 6 sacks containing 100 coins each, 5 sacks containing 10 coins each, and 6 more coins.
6 sacks containing 100 coins each = 6 times 100 = 600 coins
5 sacks containing 10 coins each = 5 times 10 = 50 coins
So, total number of coins collected by Team A
= 600 coins + 50 coins + 6 coins
= 656 coins

Team B collected 8 sacks containing 100 coins each, 2 sacks containing 10 coins each, and 5 more coins.
8 sacks containing 100 coins each = 8 times 100 = 800 coins
2 sacks containing 10 coins each = 2 times 10 = 20 coins
So, total number of coins collected by Team B
= 800 coins + 20 coins + 5 coins
= 825 coins

So, Team B collected more coins than Team A.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
Watch in App
Join BYJU'S Learning Program
CrossIcon