In a triangle A B C - if B - 30 - and c - - 3 b - then show that a2-2b2-3ab-0

B=30 #176; C=√(3b) Therefore, cos 30 #176;=c^2+a^2 b^22ca √(3)2=(√(3b))^2+a^2 b^22√(3b)a 3ab=(3b^2 b^2+a^2) ⟹ a^2+2b^2 3ab=0 ...

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Basic Trigonometric Identities

In a triangle...

Question

In a triangle $A B C,$ if $B = 30^{\circ}$ and $c = \sqrt{3} b,$ then show that a^2+2b^2-3ab=0

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