In a triangleABC, 3 A=4 B=6 C .Calculated each angle of the triangle.

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Solution

We know that, sum of angles of a triangle = A+B+C = 180 degrees
Also, it is given that 3A=4B=6C=X (say)
$S o, A = \frac{X}{3}$
$B = \frac{X}{4}$
$C = \frac{X}{6}$
$S o, \frac{x}{3} + \frac{x}{4} + \frac{x}{6} = 180$
$\Rightarrow \frac{9 x}{12} = 180$
$\Rightarrow x = 240$
$S o, a n g l e A = \frac{x}{3} = \frac{240}{3} = 80$
$B = \frac{x}{4} = 60$
$C = \frac{x}{6} = 40$

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