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Question

In a triangle ABC, a = 6, b = 3 and tan(AB2)=13. Area of triangle ABC = sq. units.

A
4
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B
16
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C
3
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D
9
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Solution

The correct option is D 9
Using Napier's rule, we can say that-
tan (AB2)=aba+bcot C213=636+3cot C2cot C2=1C2=π4c=π2Area of Δ ABC=12×6×3×sin π2=9 sq. units

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