In a triangle ABC, a = 6, b = 3 and tan(A−B2)=13. Area of triangle ABC = sq. units.
A
4
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B
16
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C
3
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D
9
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Solution
The correct option is D 9 Using Napier's rule, we can say that- tan(A−B2)=a−ba+bcotC2⇒13=6−36+3cotC2⇒cotC2=1⇒C2=π4⇒c=π2∴AreaofΔABC=12×6×3×sinπ2=9sq.units