In a triangle ABC, a : b : c = 4 : 5 : 6. The ratio of the radius of the circumcircle to that of the incircle is

$\frac{15}{4}$

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$\frac{11}{5}$

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$\frac{16}{7}$

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$\frac{16}{3}$

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Solution

The correct option is C
$\frac{16}{7}$

$\frac{R}{r} = \frac{2 a b c}{(a + b - c) (c + a - b) (b + c - a)} g i v e n = \frac{2.4.5.6}{3.5.7} = \frac{16}{7}$

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