In a $△ A B C, (a + b + c) r$ is equal to

b c sin A

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b c cos A

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b c tan A

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b c cot A

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Solution

The correct option is C $b c sin A$
$(a + b + c) r = 2 s \cdot \frac{Δ}{s} = 2 \cdot \frac{1}{2} b c sin A = b c sin A$

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