Question

In a triangleABC, A is right angle. L is a point on BC such that AL perpendicular on BC. Prove angleBAL= angleACB.

Answer 1

Consider $\Delta ABC$, Let, $\angle ABC=x$
$\therefore \angle BCA=90-x$ -------------- (1)
Now, consider $\Delta BAL$,
If $\angle ABL=x(=\angle ABC)$
$\therefore \angle BAL=90-x$ ----------- (2)
So, from (1) & (2) $\angle BCA=\angle BAL$