In a $△$ ABC, AB = AC and AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB. Then about which of the following lines is the triangle symmetrical?

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Solution

In the $△$ ABC ,
Given: AB = AC
AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB
Since, AB = AC (given), the line AD will divide $△$ ABC into two equal halves.
$∴$ $△$ ABC is symmetrical about the line AD.

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In a $△$ ABC, AB = AC and AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB. Then about which of the following is the triangle symetrical?

In a $△$ ABC, AB = AC and AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB. Then about which of the following is the triangle symmetrical?

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