In a $△$ ABC, AB = AC and AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB. Then about which of the perpendicular lines is the triangle symmetrical?
(2 marks)

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Solution

In the $△$ ABC,
Given: AB = AC
AD $⊥$ BC, BE $⊥$ AC and CF $⊥$ AB
(0.5 mark)
Since, AB = AC (given), the line AD will divide $△$ ABC into two equal halves.
(1 mark)
$∴$ $△$ ABC is symmetrical about the line AD.
(0.5 mark)

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