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Question

In a triangle ABC,AD is the altitude fromA.Given b>c,C=230 and AD=abcb2c2, then B is equal to

A
530
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B
1130
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C
870
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D
none of these
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Solution

The correct option is D 1130
AD=abcb2c2
=ksinA.b.ksinCk2(sin2Asin2C)
=bsinAsinCsin(B+C)sin(BC)
=bsinAsinCsin(πA)sin(BC)
=bsinC from ADC
sin(BC)=1
BC=900
B=900+C=900+230=1130

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