You visited us 1 times! Enjoying our articles? Unlock Full Access!

AAA Similarity

In a triangle...

Question

In a triangle ABC and DE parallel to BC , if AD= 1.5, AE=1cm and DB =3cm, find EC

Open in App

Solution

ABC and ADE are similar triangles, since DE is parallel to BC.

AD/DB = AE/EC or 1.5/3 = 1/EC, or
EC = 3*1/1.5 = 2.

EC = 2 cm.

Suggest Corrections

Similar questions

△ A B C, D E ∥ B C

\frac{A D}{D B} = \frac{2}{3}

A E = 3.7 c m

E C

D E ∥ B C

△ A B C, A D = 1.5 c m, B D = 3 c m

A E = 1 c m

E C

In a triangle ABC, BC ||DE If AD=1.5, DB=4.5, AE=1.3, EC=?

D E ∥ B C, A D = 2 c m, D B = 3 c m

A E = 1.6 c m

Δ A B C

D E ∥ B C

A D

D B =

7.2

A E = 1.8

E C = 5.4

Join BYJU'S Learning Program