In a △ABC, ∠A=100∘, ∠B=60∘. Find the value of ∠C
90∘
20∘
45∘
30∘
In the △ABC, using angle sum property:
∠A+∠B+∠C=180∘
⇒∠C=180∘−∠A−∠B
=180−100−60=20∘
⇒∠C=20∘
In a △ABC, ∠A=120∘, ∠B=60∘. Find the value of ∠C
In △ ABC, if (a+b+c)(a-b+c)=3ac, then [AMU 1996]
If 2∠A=3∠B=6∠C in a ΔABC, then ∠A, ∠B, ∠C are
In the given figure, ∠AOB=90∘ and ∠ABC=30∘. Then, ∠CAO=?
(a) 30∘
(b) 45∘
(c) 60∘
(d) 90∘