Question

In a triangle ABC, $\angle A={110}^o$ and $AB=AC$. Find $\angle B$ and $\angle C$.

Answer 1

As $AB=AC$ hence $\angle B=\angle C$ (Equal sides $AB=AC$ have equal opposite angles)

Using theorem, Sum of interior angles of a triangle is ${180}^o$ .

Therefore $\angle A+\angle B+\angle C={180}^o$

$\Rightarrow {110}^o+2\angle B={180}^o$ [GIven $\angle A={110}^o$]

$\Rightarrow \angle B={35}^o$

Hence, $\angle B=\angle C={35}^o$