Question

In a $△ABC,\angle A={60}^{\circ },\angle B={30}^{\circ }and\angle C={90}^{\circ }.$ Find the value of x when AB = 16 m .

• A. 12 m
• B. 2 m
• C. 8 m
• D. 4 m

Answer 1

The correct option is C 8 m

We have theorem :

"If the angles of a triangle are 30, 60 and 90 degrees, then the side opposite to 30 degree is half the hypotenuse"

Here, hypotenuse = AB= 16 m

So, x= $\frac{AB}{2}=\frac{16}{2}=8m$